Uniform Circular Motion: Crash Course Physics #7

Uniform Circular Motion: Crash Course Physics #7


Ever been on one of those twirly carnival
rides? You know, the ones where you get into a giant cylinder and stand against the wall, and then they spin you around like a wet salad? If you’ve had that uniquely nauseating experience, then you know that the simple act of spinning in a circle can be … intense. It also happens to be one of the most
misunderstood concepts in Newtonian physics. It’s known as uniform circular motion, and it’s what occurs when anything moves along a circular path in a consistent way. Most of the confusion about this idea has to do with the fact that things accelerate inward as they move in a circle — a kind of acceleration known as centripetal acceleration. But you’ll often hear people talking about centrifugal acceleration pushing things
outward as they move in a circle. That’s actually where centrifuges get their name!
And centrifugal acceleration isn’t wrong, exactly. It’s just … not real.
So, to explain how things really accelerate when they move in circles, let’s talk about
the physics of that ride as it spins you around — assuming you’re willing to risk stepping
inside. I’m getting dizzy just thinking about it. [Theme Music] In 1960, NASA was getting ready
to send people to space. They knew that a big part of space flight
would involve acceleration, so they wanted to test how much acceleration people could handle before they’d black out. Because that’s what happens when too much blood is forced away from your brain for too long. So engineers tested potential astronauts by putting them in a human centrifuge — Basically, a superpowered version
of those rides at the fair. They found that most people could withstand an acceleration of around 98 meters per second squared for 10 minutes — That’s about ten times the acceleration caused by gravity that you’d feel just by jumping in the air. With that in mind, let’s say we’ve been asked to calculate the safety of one of those carnival rides — which means we’ll need to figure
out how much acceleration riders would experience. There are equations we can use to do that,
because just like with all the other kinds of motion we’ve talked about so far, uniform
circular motion has four main qualities — position, velocity, acceleration, and time.
And they’re all related to each other. When it comes to uniform circular motion,
position is the most obvious quality: There’s an object, and it’s on a circular path.
But velocity is a little less intuitive. At any given moment, velocity tells you how fast the object’s going, and in what direction. And that direction … is NOT along the path of the circle. It’s actually perpendicular to the radius of the circle — along what we call a tangent. So if you draw an arrow representing the velocity on the circle, it’ll only touch the circle in one spot. OK bear with me here, as this
might seem kinda strange, but it’s true! One of the nice things about the physics
of motion is that often, you can just try it out for yourself and see what happens. So here’s a quick way to see tangential velocity in action: All you need is some string,
a key — or some other small object to tie the string to — and a wide open space so
nobody gets hurt , by a key flying around. Move the string so the key starts twirling
around in counterclockwise circles, parallel to the ground. Then, when the key is at the
point in the circle that’s farthest away from you… let go of the string. The key
flies to the left! Here’s why: In earlier episodes, we’ve
talked about inertia and the idea that if an object is in motion, it’ll remain in
that motion unless it’s acted upon by a net external force.
Which means that something moving in a straight line is going to continue moving in a straight
line unless a force — one that isn’t balanced out by other forces — turns it.
Whenever you see something turning? There’s a net external force acting on it.
That’s why, at any given moment, the velocity of an object moving in a circle will be tangent
to it. Without a force to turn it, it just flies in whatever direction it was moving
last. Once you let go of the string, you got rid of the force that was making the key turn
in circles. So it kept moving with the same velocity that
it had at the exact moment you let go — perpendicular to the string connecting it to your hand,
which was the center of the key’s circular path. And now, we can finally talk about the
mysterious force that was accelerating the key — changing the direction of its velocity
so that it moved in a circle. That force is the same reason riders on the
human centrifuge spin in a circle — in fact, it’s the reason anything moves in a circle.
That force is known as the centripetal force, and the acceleration it causes is called centripetal
acceleration. And the important thing to remember about
centripetal acceleration is that it’s always directed toward the center of the circular
path. That makes a lot of sense, if you think about
it in terms of how the velocity’s changing. The key was only turning in circles because
your hand was pulling it toward the center of a circular path.
But now think about what it’s like to be on one of those centrifuge rides — or, if
you’ve never subjected yourself to one, what it’s like to be in a car that turns
sharply. The ride — or the car — is turning in a circle, so there must be centripetal
acceleration pushing you toward the middle of that circle.
Except, it feels like you’re being pushed outward. People often attribute this sensation
to centrifugal force. But that’s not real. The reason that people confuse the centripetal
force with what feels like a centrifugal force comes down to a change in perspective
— what physicists call a frame of reference. From the frame of reference of someone standing
outside the human centrifuge, it’s easy to see what’s actually happening: As the
cylinder turns, it forces the people inside it to move in a circle. And the wall is pressing
on them to keep them turning — it’s actually pushing them toward the center of the circle!
But the person inside the cylinder just sees everything moving around with them.
From their frame of reference, it feels like they’re just being squashed against the
wall — as though there’s a centrifugal force acting on them.
But there’s nothing there to actually create that force. Which is why physicists call it
a fictitious force — it doesn’t really exist. So! Now that we know how acceleration works when you’re moving in a circle, we can finally
come up with some ways to connect position, velocity, and acceleration — and figure out
if that centrifuge ride is safe for people. But first, we have to talk about time. When
something’s moving around a circle in a consistent way — in other words, its acceleration
is constant — it’ll take a certain amount of time to return to its starting conditions.
In this case, those starting conditions are a particular point along the circular path.
We call that time the period of the motion, and the variable we use to represent it is
a capital T. Which isn’t too hard to remember, as long
as you keep in mind that the period is an amount of time. From timing the centrifuge
ride in action, we know that it takes 2 seconds to spin around once. So we’d say that the
period of its motion is 2 seconds. But sometimes it’s easier to talk about
the same idea in another way — how many revolutions does the ride make in one second? That’s
what we’d call the frequency of the motion — which we write as an f in equations.
That’s simple enough to figure out: if it takes the ride 2 seconds to make one revolution,
then it’s making one half of a revolution per second.It’s also not too difficult to
relate period and frequency with an equation: frequency is just 1, divided by the period.
Now that we’ve gotten time out of the way, let’s talk about position. We generally
talk about distance in terms of the circumference of the circle, because that tells us how many
times you’ve gone around the circle. In other words, if a centrifuge rider covers
the same distance as one circumference, we know they’ve made one revolution. And circumference
is just 2 times pi times the radius of the circle. So if that human centrifuge has a
radius of 5 meters, riders would travel 31.4 meters every revolution. Now: What about their speed? Well, in our episodes on motion in a straight line, we
talked about how average velocity is generally equal to the change in position over the change
in time — — which turns out to be a great way to describe the speed of uniform circular
motion. When the rider’s made one revolution around
the circle, they’ve covered a distance equal to 2 times pi times r — or, in this case,
31.4 meters. That’s how far they’ve traveled. And the amount of time it took was equal to
the period of the ride’s motion. That’s their change in time.
Divide the distance they’ve traveled by their change in time, and you get the speed
equation for uniform circular motion. Using that equation, we can calculate the speed
of a rider on the centrifuge — it’s 15.7 meters per second.
Next, getting the equation for the magnitude of centripetal acceleration — how strong
it is, basically — is a little less straightforward. That magnitude will be equal to the change
in velocity over the change in time at any given moment — in other words, its derivative.
Actually calculating the derivative can get complicated, but it turns out to be equal
to the speed, squared, divided by the radius of the circle.
This equation makes a lot of sense for a few reasons: First, take a look at the units.
Acceleration is measured in meters per second squared, so we already know that whatever
the equation for centripetal acceleration is, the units have to work out to meters per
second squared. And they do: square the speed, and you end
up with units of meters squared per second squared. Just divide those units by meters,
and you get meters per second squared. You can also tell from this equation that if you
increase your speed along the circular path or decrease the radius of that path, you should
end up with a higher acceleration. And that relationship between acceleration,
speed, and radius checks out in real life, too: Try spinning the key on a string faster,
or shortening the string but spinning it at the same speed. You’ll feel the key pulling
harder on your fingers, because it’s experiencing more acceleration.
And now that we have an equation for the acceleration that riders would experience on the centrifuge,
we can finally figure out if that ride is safe. We already know that their speed would
be 15.7 meters per second, and that the radius of the ride is 5 meters.
So, according to the equation for acceleration, their acceleration would be 49.3 meters per
second squared. That’s about half the acceleration that NASA found would make people black out.
So the ride is probably safe, at least for a couple of minutes. Whether that much acceleration
would be pleasant is a different story — but hey, we’re just here to make sure the ride
is safe. We’re not responsible for cleaning up the vomit once it’s over.
Today, you learned that when an object is in uniform circular motion, its velocity is
tangent to the circle and its acceleration is pointing inward. We also talked about the
difference between centripetal and centrifugal forces, and derived equations for period,
frequency, velocity, and acceleration. Crash Course Physics is produced in association
with PBS Digital Studios. You can head over to their channel to check out amazing shows
like Deep Look, The Good Stuff, and PBS Space Time. This episode of Crash Course was filmed
in the Doctor Cheryl C. Kinney Crash Course Studio with the help of these amazing people
and our equally amazing graphics team is Thought Cafe.

100 Replies to “Uniform Circular Motion: Crash Course Physics #7”

  1. why is it that PBS keeps hiring ppl with accents? is this out of the ignorant american belief that ppl with accents are somehow more intelligent?

  2. But if the Centrifugal force is fictitious, they why doesn't water in a bucket being spun around get pulled inward and spill out rather than pushed against the bottom of the bucket? Why does a child fly off one of those spinning fixtures of a playground if it doesn't hold onto the rails?

  3. Please slow down while explaining your videos… Its so hard to understand if you keep speaking really quickly

  4. When you swing a ball on a string the ball "EXERTS" a centrifugal force on your hand as a reaction to the centripetal force exerted by your hand on the ball; you thus have an action/reaction force pair that obeys Newton's Third Law, any decent book on physics will confirm this.

  5. That carnival ride is my favorite. It is the only experience that I think I am going to have in a centrifuge. I wonder how much g-force they exert. I know kingda-ka is 6 Gs(I went on it it was a-mazing)

  6. You videos have helped me so much in Physics. I couldn't find any reliable, informative and yet interesting video like these ones. I can't thank you enough. I'm more than thankful to you. 😊😊😇😇

  7. This video have cleared up my question about why the velocity is tangent to the circle. I'm satisfied. Though I feel like going insane 😂

  8. if a car is moving in a zig zag staight path.. with constant speed .. can we say it is in uniform circular motion.

  9. after having no idea what’s been going on in physics for a week and having a test on this tomorrow, it just made complete sense.

  10. just learned this and now it kinda makes a sense a little more. somewhat.

    i still suck at the math portion. i love physics… but enter the math in is a killer to my brain.

  11. wish this had more info and detail into these topics I have whole chapter on this and that just covered the the first page

  12. when an object is in uniform circular motion its velocity is tangent to the circle and its acceleration is pointing inward. thats all i need to know. thank you.

  13. I've never been to a centrifuge and the first thing that came to my mind getting to know about it is surprisingly the vomit that each one of those chambers would be filled with after each ride!🤢😅

  14. i thought it was going to the center because the opposite force of the key takes time to disappear, causing the object to move somewhat towards the center

  15. At 1:40, "the gravity you feel just by jumping in the air" is unfortunate. You "feel" gravity precisely while not jumping in the air; during the jump you're in free fall hence "weightless".

  16. Thankyou! Khans couldn't help, my physocs teacher is useless, and this is one of the only times I actually understand what it is we're doing in that class

  17. It feels like your being pushed outwards, people often attribute this sensation to centrifugal force, but that's not real. Throwing some shade right there!

  18. Centrifugal Force is A Pseudo Force. I think it's just there to make problems on circular motion solving simpler.

  19. But what uf you are going up for example if earth were flat and we go up mount everest how would force change.

  20. This video explained Uniform Circular Motion in nearly ten minutes better than my teacher in almost a week. Thank You!

  21. My question is:

    If im standing on equator, then im in a uniform circular motion around the center of the earth. then im actually doing a constant accelleration right? And accelleration i should be able to feel. even thou the motion is uniform right?

    a = (v^2) / r a = (465m/s)^2 / 6.371.000m = 0.0339m/s^2

    This acceleration should be equal to 0.003459 G-Force. Right? which is very little… but should i be able to feel it?

    I have been thinking about this for quite some time… so would be nice if someone knew the answer ! ;D

  22. So pretty cool. What happens if the 'uniform' motion is only for 170 degrees? As in F = ma = (m*v^2)/r? And you can point the developed vector with powered flywheels or maybe flywheel pairs? I would guess that if you want to try it out, I would guess that a visit or two to a local hardware store and $10.00 will tell you all you need to know. Ain't physics grand? 🙂

  23. Ma'am can you please help me with this question.
    One end of a string of length 'l' is connected to a particle of mass 'm' and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed 'v' and the tension in the string is 'T', then the net force on the particle is
    (A) T
    (B) T – (mv^2/l)
    (C) T + (mv^2/l)
    (D) 0

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